A block of mass 12 kg is held at rest against a vertical wall as shown in figure. If the coefficient of friction of the wall is u=0.5 then what will be the minimum force required?

Solution
Mass of block ( m ) = 12 Kg
                Coefficient of friction ( μ ) = 0.5
                Acceleration due to gravity (g) = 10 m/s2

According to diagram , Block is balanced by equal and opposite forces 
 ∴              F=N
   f=mg

  We know , fmax​ = μN
                           ∴          mg=μF
                                         F=mg​/μ
                                         F= 12 x 10 / 0.5
F = 240 N
solution

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