A block of mass 5 kg is thrown upwards with a velocity of 10 m/s It momentarily comes to - Science - Work and Energy

Question

A block of mass 5 kg is thrown upwards with a velocity of 10 m/s It
momentarily comes to rest at a height of 4 m What is the work done
by air friction durring this interval?

Abhay Kumar · Accepted Answer

Kinetic energy = work done by gravity + work done by friction 0
5 (m v 2)= mgh + work done by friction 0
5 * 5 * 102 = 5 * 10 * 4 + work done by friction 250-200=work done by friction 50 Joule = work done by friction

A block of mass 5 kg is thrown upwards with a velocity of 10 m/s. It momentarily comes to rest at a height of 4 m. What is the work done by air friction durring this interval?