A body is dropped from a height of 320m. The acceleration due to gravity is 10m/s^2?
(a) How long does it take to reach the ground?
(b) What is the velocity with which it will strike the ground?

Given,
h=320 mg=10 m/s2u=0Using, v2-u2=2ghor v2-0=2×10×320=6400or v=80 m/sThis is the velocity with which the body will strike the ground.Again,v=u+gtor t=v-ug=80-010=8 secThus, (i) 8 sec(ii) 80 m/s

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