# A body moving with uniform acceleration has a velocity of -11 cm/s when its x coordinate is 3.00 cm. If itsx coordinate 2 s later is -5 cm, what is the magnitude in cm/square of its acceleration?

Distance travelled,  Initial velocity,  time,
We use,
$s=ut+\frac{1}{2}a{t}^{2}\phantom{\rule{0ex}{0ex}}⇒-8=-11×2+\frac{1}{2}×a×{2}^{2}\phantom{\rule{0ex}{0ex}}⇒a=\frac{22-8}{2}=7$
Therefore magnitude of acceleration in $cm/{s}^{2}$ is 7.

• -7
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