A body of mass 10 kg slides down an inclined plane from rest Its height from the ground level is - Science - Sources of Energy

Question

A body of mass 10 kg slides down an inclined plane from rest Its
height from the ground level is 10m The inclined plane is not
smooth When the body reaches the ground its speed is 14 m/s Then
how much work is done against friction?(g=10
m/s2)

Vara · Accepted Answer

Potential energy at the highest point= Kinetic energy at the lowest point + Work done against frictionHence,Work done against friction is,W=PE-KE    =mgh-12mv2    =10×10×10-12×10×142    =1000 -980    =20 J

A body of mass 10 kg slides down an inclined plane from rest.Its height from the ground level is 10m.The inclined plane is not smooth.When the body reaches the ground its speed is 14 m/s.Then how much work is done against friction?(g=10 m/s2)

A body of mass 10 kg slides down an inclined plane from rest.Its height from the ground level is 10m.The inclined plane is not smooth.When the body reaches the ground its speed is 14 m/s.Then how much work is done against friction?(g=10 m/s^2₎