A Book contains 100 pages . a page is chosen at random. what is the chance that the sum of the digits on the page is equal to 9?

Answer :

We know Probability P ( E ) = Total number of desired events n ( E)Total number of  events n ( S)
Here we have book contains 100 pages  .
So,
Total number of events n ( S ) =  100
And
Pages that have sum of the digits on the page is equal to 9 =   {   9  ,  18  ,  27 , 36 , 45 , 54 , 63 , 72 , 81 , 90  } 
So,
Total number of desired events  n ( E ) = 10
So,
Probability of getting sum of the digits on the page is equal to 9,  P ( E ) = 10100 = 110                     ( Ans )

  • -1
I'm not sure but I think
P(Probablity)= 1 by 100 = 9
  • 0
11 by 100
  • 2
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