# A Book contains 100 pages . a page is chosen at random. what is the chance that the sum of the digits on the page is equal to 9?

We know Probability P ( E ) =
Here we have book contains 100 pages  .
So,
Total number of events n ( S ) =  100
And
Pages that have sum of the digits on the page is equal to 9 =   {   9  ,  18  ,  27 , 36 , 45 , 54 , 63 , 72 , 81 , 90  }
So,
Total number of desired events  n ( E ) = 10
So,
Probability of getting sum of the digits on the page is equal to 9,  P ( E ) =

• -1
I'm not sure but I think
P(Probablity)= 1 by 100 = 9
• 0
11 by 100
• 2
What are you looking for?