A box of mass 400kg rests on a carrier of truck that is moving at a speed of 120km/he. The driver applies brake and slow to a speed of 60km/he in 20 sec. Find the constant acceleration generated upon the box.

Dear student,
v=u+athere v=60km/hr =16.67m/su = 120km/hr = 33.33m/st = 20 sec16.67 = 33.33 +a×20-16.66 =20aa=-16.6620=-0.83m/s2This the constant deceleration
This is constant deceleration of the truck.
For the box it  will be 0.83m/s2

Regards

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