A boy increases his speed to 9/5 times of his original speed By this he reaches his - Maths - Basic Geometrical Ideas

Question

A boy increases his speed to 9/5 times of his original
speed By this he reaches his school 30 minutes before the usual
time How much time does he takes usually?
a 70 50 min
b 54 min
c 66 67 min
d 67 50 min

Ankita Agarwal · Accepted Answer

Dear Student,

Let the original Speed of the boy be S
Let the original time taken by boy to reach school be T
Original Distance D1= Speed × TimeDistance when the speed is increasedD2= 95S×T-30Distance travelled in both the cases will be same, hence D1=D2S×T=95S×T-305T=9T-305T=9T-270T= 2704= 67
5 minutes Hence, option D is correct

Regards

A boy increases his speed to 9/5 times of his original speed. By this he reaches his school 30 minutes before the usual time. How much time does he takes usually? a. 70.50 min b. 54 min c. 66.67 min d. 67.50 min

A boy increases his speed to 9/5 times of his original speed. By this he reaches his school 30 minutes before the usual time. How much time does he takes usually?
a. 70.50 min
b. 54 min
c. 66.67 min
d. 67.50 min