A bullet of 10 g strikes a sand bag at a speed of 103 ms-1 and gets embedded after travelling - Science - Force and Laws of Motion

Question

A bullet of 10 g strikes a sand bag at a speed of 103
ms-1 and gets embedded after travelling 5 cm Calculate
(i) the resistive force exerted by the sand on the bullet (ii) the
time taken by the bullet to come to rest

Shivam Kumar · Accepted Answer

Dear Student,

Given,m=10g=10-2kgs=5cm=0
05 mu=103m/sv=0comes to restThird equation of motion:v2-u2=2as0-1032=2a×0
05a=-1060 1=107m/s2
F=ma=10-2×107=-105NForce on bullet is -105N so the resistive force is 105N

Also,v=u+at0=103+(-107)tt=103107=10-4sec

Regards,

A bullet of 10 g strikes a sand bag at a speed of 10³ms^-1 and gets embedded after travelling 5 cm. Calculate (i) the resistive force exerted by the sand on the bullet. (ii) the time taken by the bullet to come to rest.

v2=u2+2as

A bullet of 10 g strikes a sand bag at a speed of 103 ms-1 and gets embedded after travelling 5 cm. Calculate (i) the resistive force exerted by the sand on the bullet. (ii) the time taken by the bullet to come to rest.

v2=u2+2as

A bullet of 10 g strikes a sand bag at a speed of 10³ms^-1 and gets embedded after travelling 5 cm. Calculate (i) the resistive force exerted by the sand on the bullet. (ii) the time taken by the bullet to come to rest.