A bullet of mass 0.02 kg is fired from a gun weighing 7.5 kg. If the initial velocity of the bullet is 200 m/s, calculate the speed with which the gun recoils.

Solution:
plying the law of conservation of linear momentumMgunVgun+mbulletvbullet =0So 7.5×Vgun +0.02×200 =0or Vgun or recoil velocity =-0.02×200 7.5 =- 0.533m/sThe negative sign shows the gun's velocity is in the opposite direction from the bullet's velocity.

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