A bullet of mass 1 kg is fired and gets embedded into a block of wood of mass 1 kg - Physics - Magnetism And Matter

Question

A bullet of mass 1 kg is fired and gets embedded into a block of
wood of mass 1 kg initially at rest The velocity of the bullet
before collision is 90 m/s What is the velocity of the system after
collision Calculate the kinetic energy before and after the
collision Is it an elastic collision or inelastic collision How
much energy is lost in collision

Sakshi Kanwar · Accepted Answer

Dear Student
Mass of bullet=1KgMass of wood=1Kgvelocity of bullet=90ms-1By conservation o f momentumm1v1+m2v2=(m1+m2)Vv2=01×90=(1+1)×VV=45ms-1This the velocity of combined systemKinetic energy=1/2×1×90×90=4050JFinal kinetic energy=1/2×45×45=2025JLoss in kinetic energy=4045-2025=2025JRegards