a buoyant force of 200 gwt acts on a body dipped completely in water. If the apperent weight of the body is 100gwt, then find its actual weight

The buoyant force acting on the body,
ρwgV=200 g wt. =200×10-3×10=2 NApparent weight=100 g wt.=100×10-3×10=1 NThe actual weight of the body=ρbgVThe apparent weight=actual weight-buoyant force 1=ρbgV-2ρbgV=3ρbgV=300×10-3×10=300 g wt.

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