a buoyant force of 200 gwt acts on a body dipped completely in water. If the apperent weight of the body is 100gwt, then find its actual weight Share with your friends Share 0 Komal Jain answered this The buoyant force acting on the body, ρwgV=200 g wt. =200×10-3×10=2 NApparent weight=100 g wt.=100×10-3×10=1 NThe actual weight of the body=ρbgVThe apparent weight=actual weight-buoyant force⇒ 1=ρbgV-2⇒ρbgV=3⇒ρbgV=300×10-3×10=300 g wt. 7 View Full Answer