A bus started his journey and reached difeferent places with the speed of 60/km per hour the distance between A and B is 4170 km,C and D is 2I60 km,E and F IS4830 KM AND G to A is 1290 km. find hout the time taken to reach a)A to B b)C to D ,c)E to G )total journey

Given Speed of bus = 60 km / hr

And

Distance between A and B = 4170 km

Distance between C and D = 2160 km

Distance between E and F = 4830 km

Distance between G and A = 1290 km

we know Time = $\frac{Dis\mathrm{tan}ce}{Speed}$ So,

a ) Time taken to reach A to B is = $\frac{4170}{60}$ = 69.5 hr ( Ans )

b ) Time taken to reach C to D is = $\frac{2160}{60}$ = 36 hr ( Ans )

c ) Time taken to reach E to F is = $\frac{4830}{60}$ = 80.5 hr ( Ans )

d ) Total time taken by bus = Time taken to reach A to B + Time taken to reach C to D + Time taken to reach E to F + Time taken to reach G to A

So,

Time taken to reach G to A = $\frac{1290}{60}$ 21.5 hr

So,

**Total time taken = 69.5 + 36 + 80.5 + 21.5 = 207.5 hr ( Ans )**

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