a charge +Q is placed on a large spherical conducting shell of radius R another small conducting sphere of - Physics - Electrostatic Potential And Capacitance

Question

a charge +Q is placed on a large spherical conducting shell of
radius R another small conducting sphere of radius r carrying
charge q is introduced inside the large shell and is placed at its
centre find the potential difference b/w two points, one lying on
the sphere and the other on the shell
how would the charge b/w the two flows if they are connected by
a conductingwire? name the device which works on this fact

Satyendra Singh · Accepted Answer

Dear
Student,
Please find below
the solution to the asked query:

(1)

Potential on the Sphere of radius 'r' carrying charge 'q':Vsphere = kqrSince sphere is inside the shell shell is conduction therefore, equal amount of negative charge will be induced on the inner surface of the charge and equal amount of positive charge will be induced on the on the surface
Potential on the surface of the shell is given by:Vshell  = k (Q+q-q)R = kQRPotential difference between the two points:V  = Vshell - VsphereV = kQR - kqrV=k×QR-qr

(2) From the above equation it is clear that the shell is at higher
potential Therefore, the charge will flow from higher potential to
lower potential, i e , from the shell to the sphere, if they were
connected by a conducting wire The device working on this principal
is called spherical capacitor

Hope this
information will clear your doubts about Electrostatic potential
and Capacitance
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Regards
Satyendra Singh