# A chord of a circle of radius 20 cm subtends an angle of 90 degree at the centre. find the area of the corresponding major segment of the circle

theta = 90 degree

area of sector = theta/360 * pi * r

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= 90/360 * 22/7 * 20 * 20

= 1/4 * 22/7 * 20 * 20

= 2200/7

314.2 cm

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area of triangle = 1/2 * base * height

= 1/2 * 20 * 20 ( base and height both are r ) = 200 cm

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Area of minor segment = 314.2 - 200 = 114.2 cm

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major segment = area of circle - 114.2

= pi * r

^{2}- 114.2

=22/7 * 20 * 20 -114.2

= 1142 .94 cm

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hope this helps...pls leave a like

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