A chord of a circle of radius 20 cm subtends an angle of 90 degree at the centre. find the area of the corresponding major segment of the circle

r = 20cm 
theta = 90 degree
area of sector = theta/360 * pi * r²
= 90/360 * 22/7 * 20 * 20
= 1/4 * 22/7 * 20 * 20
= 2200/7
314.2 cm²
area of triangle = 1/2 * base * height
= 1/2 * 20 * 20 ( base and height both are r ) = 200 cm²
Area of minor segment = 314.2 - 200 = 114.2 cm²
major segment = area of circle - 114.2
= pi * r² - 114.2
=22/7 * 20 * 20 -114.2 
= 1142 .94 cm²
hope this helps...pls leave a like