a chord of circle of radius 28cm subtends an angle 45 at the center . find the area of minor segment .

  • -3

given : thita=45degree , r=28cm

solution:- thta/360degree pi r square

=45/360*22/7*28*28

=1/8*22/7*28*28

=11*28

=308 cm square

  • 0

given: thita=45 degree , r=28

solution :- area of segment =r2(pie thita/360-1/2sin thita)

=(28)2(3.14*45/360-1/2 sin45degree)

=784(3.14/8-1/2.82)

=31.36 cm square -answer

  • 1

the answer is correct

  • 1
What are you looking for?