**A chord of circle subtends an angle 'Theta' at centre of the circle.**

**The area of the minor segment cut off by the chord is one eighth of the area of the circle.**

**Prove that 8Sin(theta)/2 * Cos(theta) + (PI) = (PI)(Theta)/45**

given : chord AB subtend angle θ at center O.

let the radius of the circle be r.

area of minor segment cut off by the chord AB

= area of sector AOB - area of triangle OAB

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