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a conductor carries a current of 0.5 A.find the amount of charge flowing in 40s.and how many electrons are passing per /min through this conductor

 Given,

i=0.5A

t= 40s

Q=it

= 0.5A x 40s

= 20C

Q= ne (where,n is number of electrons flowing in 1 s.)

=> 20C=n x 1.6 x 10-19C

=> n = 20/(1.6 x 10-19)

=> n = (20 x 1020)/16

so, n = 1.25 x 1020

so, number of electrons flowing in 1min= 1.25 x 1020 x 60

                                                         = 75 x 1020

                                                         = 7.5 x 1021

  • 10
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Current=0.5A   Time=40s                                                                                                                                                                                     We know,

I = Q/t  or, Q = It 

Therefore, Q= 0.5 * 40 = 20 Couloumb

No. of electrons flowing through the conductor/sec = 20 / 1.6 * 10-19                                                                                                  

 = 12.5 * 1019 electrons/sec

Therefore, electrons / min = 12.5 * 1019 * 60

  = 7.5 * 1021 electrons/min

  • 4

Given,

i=0.5A

t= 40s

Q=it

   = 0.5A x 40s

   = 20C

Q= ne  (where,n is number of electrons.)

 => 20C=n x 1.6 x 10-19C

=> n = 20/(1.6 x 10-19)

=> n = (20 x 1020)/16

so, n = 1.25 x 1020

  • 3
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