a cone of radius 10 cm is divided into two parts by drawing a plane through the midpoint of its axis , parallel to its base . compare the volume of the two parts
let the height of the cone be H and the radius be R.
this cone is divided into two parts through the mid-point of its axis. therefore AQ=1/2 AP
since therefore triangle AQD is similar to the triangle APC.
by the condition of similarity
volume of the cone ABC=
volume of the frustum=volume of the cone ABC-volume of the cone AED
volume of the cone AED=