A convex lens of focal length​ 0.24m and of refractive index 1.5 is completely immersed in water of refractive index 1.33. Find the change in focal length of the lens.
 

Dear Student,
f=0.24 m , μ=1.5using lens maker formula1f=1.5-11R-1R'1R-1R'=10.5f 1f'=1.51.33-11R-1R'1f'=1.51.33-110.5*0.24 1f'=98-110.121f'=18.10.12f'=0.12*8=0.96 m change in focal length=f'-f=0.96-0.24=0.72 m Regards
 

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