A convex lens of focal length 0.24m and of refractive index 1.5 is completely immersed in water of refractive index 1.33. Find the change in focal length of the lens. Share with your friends Share 2 Shobhit Mittal answered this Dear Student, f=0.24 m , μ=1.5using lens maker formula1f=1.5-11R-1R'1R-1R'=10.5f 1f'=1.51.33-11R-1R'1f'=1.51.33-110.5*0.24 1f'=98-110.121f'=18.10.12f'=0.12*8=0.96 m change in focal length=f'-f=0.96-0.24=0.72 m Regards 10 View Full Answer