A copper wire of resistivity 2.6 × 10 -8 Ω m, has a cros s sectional are a o f 35 × 10 -4 cm 2 . Calculate the length of this wire required to make a 10 Ω coil. PLEASE ANSWER FAST!!!!!!!!!!!11 Share with your friends Share 1 Rohit Babu answered this Dear Student,Given,ρ=2.6×10-8Ωm,A=35×10-4cm2=35×10-8m2,R=10ΩWe know,R=ρlALength of the wire is,l=RAρ=10×35×10-82.6×10-8=134.61mRegards. 0 View Full Answer