A costant force F=20N acts on a block of mass 2kg which is connected to two blocks of masses m1=1 kg and m2=2 kg.Calculate the accelerations produced in all the three blocks.Assume that pulleys are frictionless and weightless.

Let, F be the force applied to the system. The total mass of the system is m = 2kg + 1kg + 2kg = 5 kg

So, acceleration of the system, a = F/m = (20/5) m/s ^{ 2 }

thus,

a = 4 m/s ^{2 }

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