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A cricket ball of mass 150g is moving with a velocity of 12m/s and is hit by a bat, so that the ball is turned back with a velocity of 20m/s. The force of the blow acts for 0.01s on the ball. Find the average force exerted by the bat on the ball.

Mass of the ball, m = 150 g = 0.15 kg

Initial speed of the ball, u = -12 m/s

Final speed of the bal after being hit, v = 20 m/s

Impulse = change in momentum = final momentum initial momentum

= Impulse = 0.15 × 20 0.15 × (-12) = 4.8 Ns

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  • -24
Force = ma
So, 150*20-150*12
=1200N
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vy=uy+at              
vy=o
uy=usin(tita)      
vy=uy+at
0=usin(tit)+(-g)t(because acceleration due to gravity is acting downwards (i.e a= -g))
0=usin(tit)-gt
-usin(tita)= -gt
usin(tita)=gt       (- and - gets cancelled)
t=usin(tita)/g
 
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Mass of the ball, m = 150 g = 0.15 kg

Initial speed of the ball, u = -12 m/s

Final speed of the ball after being hit, v = 20 m/s

Impulse = change in momentum = final momentum initial momentum

= Impulse = 0.15 × 20 0.15 × (-12) = 4.8 Ns

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Here sign convention is used so that one velocity will be positive and other will be negative

  • 49
12*10^-3
  • -7
1200N
  • -6
Mass of the ball, m = 150 g = 0.15 kg Initial speed of the ball, u = -12 m/s Final speed of the bal after being hit, v = 20 m/s Impulse = change in momentum = final momentum initial momentum = Impulse = 0.15 × 20 0.15 × (-12) = 4.8 Ns
  • -3
Please find this answer

  • 4
480N
  • 2
Mass of the ball, m = 150 g = 0.15 kg

Initial speed of the ball, u = -12 m/s

Final speed of the ball after being hit, v = 20 m/s

Impulse = change in momentum = final momentum initial momentum

= Impulse = 0.15 ? 20 0.15 ? (-12) = 4.8 Ns
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Please find this answer

  • 1
Mass of ball=150\1000=0.15kg

Velocity of ball =12m\s

Momentum of ball =0.15kg *12m\s =1.8kg m\s

Velocity after collision =20m\s

Momentum of ball =0.15*20 =3kg m\s
Time of contact =0.01s

Av.force = change in momentum ime of contact

= 3 -1.8\0.01s =120 newton
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