A current of 2A passes through a circuit for 1 minute. If the potential difference between the terminals of the circuit is 3V, what is the work done in transferring the charges
I = 2 A
t =1 minute =60 seconds
V =3 V
We know that I = Q/t
Therefore Q =It
= 2×60
=120 Coulombs.
We know that V = W/Q
Therefore W =VQ
= 3 × 120
= 360 Joules.
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t =1 minute =60 seconds
V =3 V
We know that I = Q/t
Therefore Q =It
= 2×60
=120 Coulombs.
We know that V = W/Q
Therefore W =VQ
= 3 × 120
= 360 Joules.
Thumbs up plz