A die is thrown 1000 times with frequency of outcome 1,2,3,4,5, and 6 as given below

outcome 1 2 3 4 5 6

Frequency 179 150 157 149 175 190

A die is thrown once again. Find the probability of outcome "greater than 3" ?

A die is thrown 1000 times

Total number of trials = 1000

P(an event) =

We need probability of an outcome which is greater than 3 = sum of the number of times 4, 5, 6 appears. = 149 + 175 + 190 =514

Number of favorable outcomes= 514

P(greater than 3) = = 0.514

  • 4

probability= total no of times dice thrown no.of times outcome greater than 3

=> 149+175+190/1000

=>514/1000

  • 2
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