a die is thrown 400 times with the frequency for the out comes 1,2,3,4,5,6, given in the following table outcomes frequency 72,65,70,71,63,59. find the probablity of 1)geting a number less than 3 2)geting number more than 4 Share with your friends Share 1 Varun.Rawat answered this Total number of times a die is thrown = 400Total number of possible outcomes = 4001.Number of times '1' appears = 72Number of times'2' appears = 65Number of times a number less than 3 appears = 72 + 65 = 137Number of favourable outcomes = 137Required probability = Number of favourable outcomesTotal number of possible outcomes = 1374002.Number of times '5' appears = 63Number of times'6' appears = 59Number of times a number more than 4 appears = 63+59 = 122Number of favourable outcomes = 122Required probability = Number of favourable outcomesTotal number of possible outcomes = 122400 = 61200 7 View Full Answer Binnyhanu answered this 1) P( getting a number less than 3 ) = 72+65/400 = 72.1625 2) P ( getting a number more than 4 ) = 63+59/400 = 63.1475 -3