# A die is thrown 50 times and it showed the number 1, 23times. find the probability of getting a number other than 1 in the next throw of the die.

the probability of getting number 1 in  a throw = 23/50
therefore the probability of getting number other than 1
$=1-\frac{23}{50}\phantom{\rule{0ex}{0ex}}=\frac{50-23}{50}\phantom{\rule{0ex}{0ex}}=\frac{27}{50}$

hope this helps you

• 25
50-23 = 27
27/50 = 0.54
Thumbs up plz......
• 3
Probability =  favourable outcome
Total possible outcome.
Number of times the number one is shown = 27.
Number of time other number is thrown = Number of time a die is thrown - Number of time 1 has been shown.
= 50-27
= 23
P(getting a another number is) = 23
50
=0.46
• 4
Sorry its 50-23 = 27
= 27/50 = 0.54
• 2
What are you looking for?