# A die is thrown 50 times and it showed the number 1, 23times. find the probability of getting a number other than 1 in the next throw of the die.

therefore the probability of getting number other than 1

$=1-\frac{23}{50}\phantom{\rule{0ex}{0ex}}=\frac{50-23}{50}\phantom{\rule{0ex}{0ex}}=\frac{27}{50}$

hope this helps you

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