A first order reaction is 50% complete in 30 minutes at 27° C and in 10 minutes at 47 ° C.calculate the activation energy.
It is a first order reaction and reaction is 50% completed (that is half life period) in 30 min at 270C and in 10 min at 470C
From this we can calculate k1 and k2.
k1 = 0.693/t1/2 at 270C
= 0.693 / 30 = 0.0231
k2 = 0.693/t1/2 at 470C
= 0.693 / 10
T1 = 273 + 27 = 300K
T2 = 273 + 47 = 320K
After putting all the values in the given formula you will get the value of activation energy.