a flask containing 250mg of air at 27 degree C is heated till 25% of air by mass is expelled from it.what is the final temperature of the flask

Dear Student,

Letthe volume of he flask be V and the final temperature be TSo, mass of air expelled at T =25100×250=62.5 gMass of air remaining in flask =250-62.5 =187.5 gNow, the volume of total air at higher temperatureV2=V×250187.5and, applying Charles's lawV2T=V300or,T= V2×300V=V×250×300V×187.5=400 K = 127°C

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