A flower pot drops from the edge of the roof of a multi storied building.Calculate the time taken by the pot cross to a particular distance AB of height 2.9 m , the upper point A being 19.6 m below the roof.

v= final velocityu = initial velocitya = g= accelerations= displacement coveredsince the pot has been dropped.u = 0m/slet's calculate the final velocity when pot reaches 19.6m below roof.s=ut+1/2(g)(t)2s=1/2(g)(t)219.6=0.5*9.8*t2t=2 secv=atv=9.8*2=19.6m/sTime taken for that particular height 2.9 m 2.9=ut+0.5at22.9=19.6t+4.9t219.6t+4.9t2-2.9=0t=0.14285714285714324 sec

  • -3
What are you looking for?