a force F=(3x^2yicap +x^3jcap) is acting on a particle. find work done by the force during displacement of the particle from (1m,1m) to (2m,-1m)

Dear studentGiven F=3x2yi^+x3j^and points (1m, 1m) and (2m, -1m)now displacement ds=(i^+j^)-(2i^-j^)=-i^net workdone W=F.dsW=123x2y. dxW=8y-y=7yregards

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