a force F=-K(yi+xj), where K is a positive constant,acts on a particle moving in a x-y plane.. starting from the origin yhe particle is taken alon positive x axisto a point (a,0) and then parallel to y axis to a point (a,a.) calculate the total work done by force on the particle.

**Solution:**

We know that,

Work done=Force x displacement

For origin to (a,0), the total work done=W

=ai[-K(yi+xj)]=-Kay=0

For (a,0) to (a,a),the work done=W'

=(aj+ai-ai).[-K(yi+xj)]=-Kax=

So the total work done=W+W'=0=

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