A force of 500 N is acting towards east and another of 600 N towards north. Subtract the first force from the second by drawing a vector diagram.
hi Kavita
Please find below the solution to the asked query:
(if image is not completely visible kindly open in new tab.)
In the diagram the R vector = [(600)2 + (-500)2]1/2
R = [360000 + 250000]1/2 = 6100001/2
R = 781.02 N
This is reult of the subtraction of the vector through diagram
than angle that that R vector makes with the 500 N vector is
Tanθ = 600/500
θ = Tan-1(6/5)
= 50.19o
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Please find below the solution to the asked query:
(if image is not completely visible kindly open in new tab.)In the diagram the R vector = [(600)2 + (-500)2]1/2
R = [360000 + 250000]1/2 = 6100001/2
R = 781.02 N
This is reult of the subtraction of the vector through diagram
than angle that that R vector makes with the 500 N vector is
Tanθ = 600/500
θ = Tan-1(6/5)
= 50.19o
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.