A force of 500 N is acting towards east and another of 600 N towards north. Subtract the first force from the second by drawing a vector diagram.

hi Kavita 

Please find below the solution to the asked query:

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In the diagram the R vector = [(600)+ (-500)2]1/2

R = [360000  +  250000]1/2  =  610000

R = 781.02 N

This is reult of the subtraction of the vector through diagram

than angle that that R vector makes with the 500 N vector is

Tanθ​  = 600/500

θ​  = Tan-1(6/5)

   = 50.19o

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