A gun of mass 20kg has a bullet of mass 0.1kg in it.804J of recoil energy is released on firing the gun. What is speed of bullet in m/s

Let the momentum of the gun is Pg.
Eg=Pg22mgPg=2mgEg=2×20×804=179.33 kgm/s
Momentum of the bullet is same as Pg.
Speed of the bullet,
v=179.330.1=1793.3 m/s

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40.2m/s
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