# A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm, find the outer curved surface area of the bowl. (Take pie=3.14)

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2πr2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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Thank u for the answer ! It was helpful

• -6

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2r2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

• 1

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2r2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

• -4

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2r2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

• 9
the actual thickness is 5 cm
the hemispherical bowl is made of steel its thickness is =0.25cm
outer radius of hemispherical bowl = (5+0.25)cm
=5.25 cm
outer C S A of hemisphere bowl=2(pie) r square.
therefore the outer C S A of the bowl is 173.25 cm square.
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Answer

• -2
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