A line passes through P(1,2) such that its intercept between the axes is bisected at P. Find the equantion of the line.

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Please find below the solution to the asked query:

Let X-axis intercept of line be Aa,0 and Y-axis intercept of line be 0,b.Hence equation of line will be:xa+yb=1According to question P1,2 is mid point of Aa,0  and B0,ba+02=1 and 0+b2=2a=2 and b=4Hence equation of line will be:x2+y4=1Multiplying each term by 4 we get:2x+y=42x+y-4=0

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