a man stands in between two high raised building & blows a whistle.He hears two successive echos after 0.4s & 1.6s.Calculate the distance between the building.speed of sound is 332m/s.
Speed of sound, v = 332m/s.
Suppose he is standing x1 distance away from the first and x2 distance away from the second building and (x1<x2). He hears two successive echos after 0.4s & 1.6s,
Which means to cover double the distance ie 2x1 he takes 0.4 sec Then x1 = (0.2) v metres
To cover double the distance from the second building ie 2x2 he takes 1.6 sec Then x2 = (0.8) v metres
Hence, net distance between the both building, x = x1+x2