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A MAN STARTS WALKING FROM HIS HOUSE. THEN WALK 3 KM NORTH AND THEN 5 KM RIGHT . HOW FAR HE IS FROM HIS HOUSE. FIND BY PYTHAGORAS THOEROM


Let O be the starting point where the man's house is located.Suppose he travels 3 km towards North and reaches point A.From A, he travels 5 km towards right that is towards East and reaches B.Now, we have to calculate OB.By Pythagoras Theorem,OB = OA2+AB2=32+ 52=9+25=34=5.83 km

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Sorry to tell but the question you asked is wrong because the hypotenuse should be the longest side.
It can be that he walks 3 km north and 4 km east. Find distance from his house.
Then it would be like:

In triangle ABC, <A=90 degrees.
BC2=AB2+AC2
BC2=32+42
BC2=9+16
BC2=25
BC=5
He is 5 km away from his house.
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