A metal cuboid of mass M kg rests on a table surface are of 40 cm? in contact with the table. The pressure exerted by the cuboid on the table surface is 10000 Pa(Pascal). Value of M is (given that g=10 ms-? or 10 ms ^ -2)

Solution,
Area of the base of the cuboid which rests on a table, A = 40 cm2
Pressure exerted by the cuboid on the table, P = 10000 Pa
P=ForceArea=Weight of the cuboidbase area resting on the table=MgAP=MgAM=PAg=10000Pa×40×10-4m210ms-2=4kg

  • 0
What are you looking for?