# A metal cuboid of mass M kg rests on a table surface are of 40 cm? in contact with the table. The pressure exerted by the cuboid on the table surface is 10000 Pa(Pascal). Value of M is (given that g=10 ms-? or 10 ms ^ -2)

Area of the base of the cuboid which rests on a table, A = 40 cm

^{2}

Pressure exerted by the cuboid on the table, P = 10000 Pa

$P=\frac{Force}{Area}=\frac{Weightofthecuboid}{basearearestingonthetable}=\frac{Mg}{A}\phantom{\rule{0ex}{0ex}}P=\frac{Mg}{A}\phantom{\rule{0ex}{0ex}}M=\frac{PA}{g}=\frac{10000Pa\times 40\times {10}^{-4}{m}^{2}}{10m{s}^{-2}}=4kg$

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