# A metal pipe is 77cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. Find its(i)inner curved surface area(ii)outer curved surface area(iii)total surface area

Length of pipe = 77 c.m.

Inner diameter = 4 c.m.

Outer diameter = 4.4c.m.

1) Inner curved surface area

radius = inner diameter  / 2       => 4 c.m./2      => 2 c.m.

curved surface area = 2 / rh    =>  2* 22 * 77              => 2 *22* 11 = 968 c.m.2

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2). Outer curved surface area

radius = outer diameter  / 2             =>  4.4 c.m. / 2        => 2.2 c.m.

curved surface area =  2 / rh

= 2 * 22* 2.2* 77

__________________                   =>   1064.8 c.m.2

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3)   total surface area

surface area on the end = 2 / ( R+r )( R -r )

= 2 *22 * ( 2.2 + 2) ( 2.2 -2)

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= 2* 22* 4.2 * 0.2

________________                       = 5.28 c.m.2

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total surface area = 968 c.m.2 + 1064.8 c.m.2 +5.28 c.m.2 = 2038.08 c.m. 2

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How his Total surface area=(Csa of inner + Csa of of outer part )+ Difference in top areas

Tell me the one in brackets

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Nnn
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Ikr
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thanks for the answer but im better than u at math loser
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Hey Uttham are you from Rewa??Rajhans School???
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Bhavna ji 3rd point nahi samajh aaya kaise kari hain aap?????
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A better solution for the third one pls
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Hlo
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It is not 4.4 it is 4.8
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I think you should ask valuable questions instead of hi/hello.better for next time to these students
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Outer curved surface area and the last 1 total surface area both were wrong please correct it I had seen by my answer sheet of maths class 8
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I think meritnation app should take action on those who dont make proper use of this. Plzz make it valuable not for gossip purpose..for gossip what's app is there Thank you
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2038.08cm2
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