A metre stick is held vertically with one end on the floor and is allowed to fall . What will be the speed of the other end when it hits the floor assuming that the end at the floor does not slip.
ans; 5.4m/s
Here we shall use the law of conservation of energy
for the other end of the meter stick
potential energy = kinetic energy
now, as the scale is rotating as well
mgh = (1/2)mv2 + (1/2)Iw2
as v = rw and r = 1m
so,
mgh = (1/2)mv2 + (1/2)Iw2
or
mgh = (1/2)v2(m+I)
if we know I then the speed can be calculated using the above relation.