A MOTOR BOAT WHOSE SPEED IS 20KM/H IN STILL WATER, TAKES 1 HOUR MORE TO GO 48 KM UPSTREAM THAN TO RETURN DOWNSTREAM TO THE SAME SPOT FIND THE SPPEED OF THE STREAM
IF THE ROOTS OF THE EQ (a2 +b2)x2 - 2(ac+bd)x + (c2+d2)c = 0 EQUAL PROVE THAT a/b = c/d
Velocity of boat in still water(v) = 20 km/hr
Let the velocity f the stream be x km/hr
So velocity of the boat during upstream is (20-x) km/hr
Velocity of the boat during downstream is (20+x) km/hr
So according to the question
Neglect the negative value.
So the velocity of the stream is 4 km/hr.