# a number cube has its sides numbered as 1,2,4,6,7 and 5.if a cube is thrown once, what is the probability of rolling of an odd number?

Please find below the solution to the asked query:

We know formula for probability :

Probability P ( E ) = $\frac{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{desired}\mathrm{events}\mathrm{n}(\mathrm{E})}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{events}\mathrm{n}(\mathrm{S})}$

Here , A cube has its sides numbered as 1 , 2 , 4 , 6 , 7 and 5

So,

n ( S ) = 6 ( As we have six sides of cube )

And

Total number of desired events = 5 and 7 ( As these are the odd numbers in given numbers )

n ( E ) = 2

Therefore ,

Probability of getting an odd number = $\frac{2}{6}=\mathbf{}\frac{\mathbf{1}}{\mathbf{3}}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{(}\mathbf{}\mathbf{Ans}\mathbf{}\mathbf{)}$

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