a number cube has its sides numbered as 1,2,4,6,7 and 5.if a cube is thrown once, what is the probability of rolling of an odd number?

Dear Student,

Please find below the solution to the asked query:

We know formula for probability :

Probability P ( E )  = $\frac{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{desired} \mathrm{events} \mathrm{n} ( \mathrm{E} )}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{events} \mathrm{n} ( \mathrm{S} )}$

Here , A cube has its sides numbered as 1 , 2 , 4 , 6 , 7 and 5

So,

n ( S ) = 6  (  As we have six sides of cube )

And

Total number of desired events = 5 and  7  (  As these are the odd numbers in given numbers )

n ( E ) = 2

Therefore ,

Probability of  getting  an odd number = $\frac{2}{6} =\mathbf{ }\frac{\mathbf{1}}{\mathbf{3}}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)}$

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