# A pair of die is thrown. Find the probability of getting a sum of 10 or more if 5 appears on the first die. pls give answer step by step.

In throwing a dice, total possible outcomes = {1, 2, 3, 4, 5, 6}

n(S) = 6

For two dice, n(S) = 6 x 6 =36

Favourable cases where sum is 10 or more with 5 on first dice {(5,5), (5,6)}

Event of getting sum is 10 or more with 5 on first dice = n(E) = 2

Probability of getting sum of 10 or more with 5 on first dice = n(E)/n(S) = 2/36 = 1/18

Regards

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