A park, in the shape of a quadrilateral ABCD, has C = 90, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m How much area does it occupy? in answer how bd=13m comes?
Considering right triangle BCD, we have;
And area of triangle BCD =
Now perimeter of triangle ABD = AB + BD + AD = 9 m + 13 m + 8 m = 30 m
so, semi perimeter of triangle ABD;s =
So using heron's formula we have;
Area of triangle ABD =
Therefore area of quadrilateral ABCD = area of triangle ABD + area of triangle BCD
In triangle BCD ,angle C is 90 degree
So, it is a right-angled triangle
BD^2= BC^2 + CD^2
SO,BD= root(144+25)= root 169= 13 m
Now , find the area of triangle BCD=1/2 * 12*5 = 30 m^2
Now, find the area of triangle ABD by Herons formula
Now , add both areas.....
U will get d ans..!