a particle of mass m carrying a charge q is accelerated by a potential difference v. it enters perpendicularly in a region of uniform magnetic field B and executes circular arc of radius R, then q/m equals?
1) 2v/B2R2 
pl show the method.[the ans- (1)]

Let v be the velocity of the particle of charge q, when accelerated through potential difference V. Then
12mv2=qV     ....,.1As the particle describes a semicircular path in the magnetic field. SoqvB=mv2Rv=qBRm     .....2Puting this value in equation 1, we get12mqBRm2=qVqm=2VB2R2

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