A particle of mass m is projected with a velocity 6i+8j.the change in momentum of projectile when it just reaches the ground is : 1.0m 2.12m 3.16m 4.20m Share with your friends Share 1 Neha Gupta answered this initial velocit is v = 6i + 8 j m/svelocity of the particle will remain same in x directio therefore change in momentum in x directio is zero.initial velocity in y direction is 8 m/sfinal velocity in y direction is -8 m/schange in velocity =8-(-8 )= 16 m/schange in momentum = mass×change in velocity = 16 m 1 View Full Answer