A particle starts from rest with an acc. of 2m.s^2 The acceleration of the particle decreases down to zero uniformly during time interval of 4s.The velocity of particle(in m/s) after 2s.


Dear Student,
                       here let rate of decreasing accelaration is Tthen T=dadt-----104Tdt=20da   (T is constant)4T=-2T=-1/2so accelaration at t=202Tdt=2a'da-1=a'-2a'=1now from 1  Tdtdvdv=daTdv=adaor     0vTdv=21ada=a2221=-3/2-v/2=-3/2v=3m/s
by the this is not in your syllabus
Regard

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