A particle starts from rest with an acc. of 2m.s^2 The acceleration of the particle decreases down to zero uniformly during time interval of 4s.The velocity of particle(in m/s) after 2s. Share with your friends Share 0 Vijay Shankar Yadav answered this Dear Student, here let rate of decreasing accelaration is Tthen T=dadt-----1∫04Tdt=∫20da (T is constant)4T=-2T=-1/2so accelaration at t=2∫02Tdt=∫2a'da-1=a'-2a'=1now from 1 Tdtdvdv=daTdv=adaor ∫0vTdv=∫21ada=a2221=-3/2-v/2=-3/2v=3m/s by the this is not in your syllabus Regard -1 View Full Answer