A person is standing between 2 vertical cliffs and 640 m away from the nearest cliff he shouted . he heard the first echo after 4 sec and the second echo 3 sec later. calculate
a) velocity of sound in air
b) distance between the cliffs
According to question,x=640m
Consider that the echo of 4 sec and 3 sec are produced by are produced by cliff A and B.
Then 2 x 640=speed of sound x 4
Speed of sound=2 x 640/4=320m/s
Again 2y=320 x 3=960
Distance between cliffs=x+y=640+480=1120m
Hence, distance between two cliff = 640 + 1120 = 1760m.