a person standing between two vertical cliffs and 640m away from nearest cliff shouted he heard first echo after 4 sec and second echo 3 sec later. calculate
(i) velocity of sound in air
(ii) distance between cliffs
1) velocity of sound in air = ( distance/ time) = (640/ 4) ms-1 = 160 ms-1
2) distance of second cliff = speed X time = {160 X (4 + 3)} m =1120 m
Distance between cliffs = (640 + 1120) m = 1760 m